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Induction motor rotates 1400 rpm and slip speed is 100 rpm fed from power supply is 210 V. Calculate the rotor full torque when the impedance is 3+J0,2 Ω.

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To calculate the rotor full torque of the induction motor, we can use the formula:
T = (3 * V^2) / (2 * w * R2)
Where:
T = Torque (in Nm)
V = Voltage supplied to the motor (in volts)
w = Angular velocity of the motor (in rad/s)
R2 = Rotor impedance (in ohms)
Given:
V = 210 V
Angular velocity = 2 * π * (1400 / 60) = 146.67 rad/s (since 1 revolution = 2π radians and 1400 rpm)
R2 = 3 + j0.2 Ω
Now, we need to convert the impedance to rectangular form:
R2 = 3 + j0.2 = 3 + j(0.2)
Now, we can calculate the torque:
T = (3 * 210^2) / (2 * 146.67 * (3 + j0.2))
T = (3 * 44100) / (293.34 * (3 + j0.2))
T = 132300 / (293.34 * (3 + j0.2))
T = 132300 / (880.02 + j58.67)
T = 132300 / √(880.02^2 + 58.67^2)
T = 132300 / 882.45
T = 149.79 Nm
Therefore, the rotor full torque of the induction motor with a rotor impedance of 3 + j0.2 Ω is 149.79 Nm.
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